Use the kaon CP eigenstates convention , matching kaon CP mixing parameter. Then is CP even, while is CP odd. With CPT symmetry and a common small mixing parameter, the physical states can be written
Here mean short and long mean lifetimes; the kaon CP mixing parameter depends on the flavor-state phase convention. A positive flavor-exchange convention instead makes the symmetric flavor combination CP even, as explained in exchange-positive CP convention for neutral kaon mixing. Mixing these conventions would reverse the interpretation of the written sums.
Why does the two-pion final state test CP symmetry? A spin-zero kaon decaying into two spin-zero pions has relative orbital angular momentum by angular momentum conservation. Two negative intrinsic parities multiply to plus, and . Charge conjugation exchanges and ; the state is even under this exchange. Hence this two-pion state has CP eigenvalue . If a decay transition operator preserves CP symmetry, inserting CP on both sides of changes its sign without changing its value: that decay amplitude must vanish.
Assume for illustration that CP violation occurs only through the state admixture and the decay transition preserves CP symmetry. Put . Then
Neglecting the tiny difference in two-body Lorentz-invariant phase space between the physical masses gives . A branching fraction, however, divides a partial decay width by the total decay width. With , , so
For chosen values and , the branching fraction ratio is , whereas the partial decay width ratio is . This is original arithmetic, not a historical fit. The longer observation time amplifies the integrated fraction relative to the instantaneous partial decay rate.

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