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Consider an ideal spherical collapse with a vacuum exterior of constant mass $M$. Once pressure support is insufficient, a surface can continue inward and cross the Schwarzschild event horizon $r_s=2GM/c^2$ in finite comoving proper time. An event horizon is a causal boundary: light emitted from inside cannot reach distant observers. It is not a material shell or, in the classical Schwarzschild solution, a local curvature singularity at $r=r_s$.

The distant view of gravitational collapse differs from the surface clock's history. Exterior Schwarzschild time has $dt/d\tau \propto (1-r_s/r{)}^{-1}$ for regular infall and diverges as the surface approaches the horizon. Outgoing radial light also takes an increasingly long coordinate time to escape: $dt/dr=[c(1-r_s/r){]}^{-1}$ has a logarithmically divergent integral at the horizon. Signals received far away are progressively delayed and redshifted; both gravity and the inward emitter's Doppler shift contribute. photons carry less received energy and arrive at a lower rate, while the available escape directions also narrow.

Thus a distant observer does not receive a light signal announcing the crossing; the image fades and reddens rather than remaining a permanently bright frozen surface. A finite-band detector with finite sensitivity loses it in finite observation time. The divergence of one coordinate chart does not prevent the material crossing in finite proper time; horizon-regular coordinates describe that continuation. The pressureless Oppenheimer-Snyder model makes this distinction explicit, without representing all the pressure, rotation and radiation of a real stellar collapse.^[ref]

The plotted example is a test-particle geodesic falling from rest at infinity, used to isolate the coordinate and signal effects; it is not a fitted stellar-collapse light curve. No actual observer can hover on the horizon to supply a static local frame there.