Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 70 2 b Solution Created 2026-10-03 Updated 2026-10-07
Define and use the outgoing acoustic square-root branchFor positive real frequency reached from below, on the propagating interval and is positive real for . The outgoing field in the lower fluid has pressure amplitude , since . If , the shared normal velocity is . The linear homentropic acoustic equations therefore giveThis lower-fluid wave is outgoing; no additional incoming sound is included in defining the impedance seen by the upper fluid.
Put . The sheet's force balance gives , hence . Its prescribed downward velocity amplitude is . Thus the tensioned-sheet acoustic impedance isThe first term is the lower fluid's normal acoustic impedance, and the second is the sheet's inertial and elastic-sheet tension response. For a real propagating angle, .
At fixed nonzero frequency and fixed wavenumber, gives , a zero-velocity, in-phase reflecting boundary. At fixed , gives the same reflection limit, but there is an important exception: elastic-sheet tension does not resist the spatially uniform mode . At normal incidence, the impedance remains however large the elastic-sheet tension is. With this mode is transparent. By contrast, arbitrarily large mass resists even a spatially uniform oscillation. These fixed-frequency limits exclude a simultaneously tuned structural resonance.
If , and . The identical fluids are effectively joined across a massless, untensioned interface: pressure and normal velocity continue without reflection. This is the matched case, rather than the pressure-release case.
Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 70 2 c Solution Created 2026-10-03 Updated 2026-10-07
With no incoming wave, both fluids obey the outgoing acoustic square-root branch. Their surface pressure amplitudes areSubstitution in the sheet's force balance yields the dispersion relation for an acoustic membrane wave:The equivalent denominator is useful away from the branch points . For real guided modes with , this is the familiar added mass of an evanescent fluid layer formThe normal fields decay away from the sheet; continued by analytic continuation roots may describe radiating or leaky modes.
On , , so the impedance from the preceding solution isThus the divergence of the reflection coefficient corresponds to a reflection pole of a fluid-loaded membrane. The prescribed incoming amplitude is zero, but a homogeneous fluid-sheet mode can have nonzero amplitude. This is a resonance or guided-mode pole of the analytic scattering problem, not arbitrarily large passive reflection at a real propagating angle. In particular, an undamped guided mode has an evanescent normal field and therefore a complex incidence angle in the plane-wave continuation. For real propagating incidence, and the finite-mass, finite-tension sheet has a purely imaginary structural impedance, so its passive reflection remains bounded.
Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 70 2 d Solution Created 2026-10-03 Updated 2026-10-07
Use the Fourier transform pair , . The point force transforms to . With the dispersion relation defined above, the sheet equation becomesThe point-force radiation from a fluid-loaded sheet is therefore represented exactly byThe causal contour and outgoing acoustic square-root branch are fixed first with , then continued to the desired real frequency. This prescription fixes how poles and the branch points are passed.
For the acoustic far field , , take bounded away from grazing and . The method of steepest descent saddle point is , with . The supplied saddle point rule, including its factor, gives, provided the contour deformation crosses no poles,A convenient simplification, free of division by , isEquivalently, when ,The expression printed in the PDF is missing sound-speed factors for general dimensional . It agrees with this result if in fully normalized units; when is retained as an arbitrary sound speed, the numerator needs and the structural term needs in the last form. These factors arise respectively from cylindrical spreading, the pressure-density relation, and .
A direct countercheck is the transparent-sheet limit . The sheet jump condition then gives , so the saddle point rule requiresThe printed expression, interpreted continuously after multiplying out its structural factor, instead gives times the same phase. It differs by a factor ; for example it is eight times too large when . This limit also verifies the normalization of the corrected density field independently of the sheet's elastic-sheet tension.
To decide about poles, track the roots of on the chosen square-root sheet and deform the original causal contour to the steepest descent contour. A root contributes a residue exactly when it lies in the region swept out by that deformation; its sign is fixed by the contour orientation. Branch cuts must be retained throughout this comparison. Which roots are crossed can depend on observation angle, producing a change of the modal contribution when a pole meets the deformation boundary. A saddle point approaching a pole or a grazing endpoint requires an approximation uniform in that limit, rather than the isolated saddle point formula above.
The crossed poles are the free fluid-sheet modes of the preceding solution. Real subsonic roots represent evanescent acoustic surface waves carrying energy along the sheet, with normal decay; complex continuations represent leaky or radiating modes. Their residues must be added to the saddle point sound when the causal contour selects them. The specification “no poles contribute” is therefore a substantive condition on the contour, not permission to ignore zeros of the dispersion relation.