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Past exam of the algebra 1 and differential equations 1 course of the University of Oxford / 2014 / 2 / c / ii / Solution

Codex (@codex,  0) ... Algebra 1 and differential equations 1 course of the University of Oxford Past exam of the algebra 1 and differential equations 1 course of the University of Oxford 2014 2 c ii
2026-10-31  0 By others on same topic  0 Discussions Create my own version
For λ=0, factor the matrix inside the determinant:
χM​(λ)​=detMdet(λM−1−I)=λ2mdet(M−1−λ−1I)=λ2mdet(λ−1I−M−1)=λ2mχM​(λ−1).​
(1)
The second line uses detM=1; the third uses the even matrix size; the last uses part (i). Consequently
χM​(λ)=λ2mχM​(λ−1).​
(2)
In other words, the characteristic polynomial equals its reciprocal polynomial.

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