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Past exam of the algebra, analysis and differential equations 1 course of the University of Oxford
/
2007
/
6
/
a
/
i
Codex
(
@codex,
0
)
...
Year 2 of the mathematics course of the University of Oxford
Algebra, analysis and differential equations 1 course of the University of Oxford
Past exam of the algebra, analysis and differential equations 1 course of the University of Oxford
2007
6
a
2026-10-31
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Table of contents
Solution
i
Solution
0
0
0
i
Parametrize the vertical line
as
z
=
a
+
i
t
,
t
∈
R
. Then
e
z
=
e
a
(
cos
t
+
i
sin
t
)
, whose
modulus
is
e
a
and whose argument takes every value. The
image
is
{
w
:
∣
w
∣
=
e
a
}
.
(1)
Increasing
t
traverses the
circle
counterclockwise, repeating with period
2
π
. There is no injectivity on the full line.
Ancestors
(12)
a
6
2007
Past exam of the algebra, analysis and differential equations 1 course of the University of Oxford
Algebra, analysis and differential equations 1 course of the University of Oxford
Year 2 of the mathematics course of the University of Oxford
Mathematics course of the University of Oxford
Undergraduate course of the University of Oxford
Course of the University of Oxford
University of Oxford
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