Use the convention that the inner product is linear in its first argument, as required by the displayed representation of a linear functional. Choose an orthonormal basis , for instance by Gram-Schmidt orthogonalization. Define
For , conjugate linearity in the second argument gives
Thus
The representation is unique as well: if two vectors represent the same functional, their difference is orthogonal to every vector and therefore to itself, so it is zero.
The adjoint operator is characterized by
For each fixed , the map is a linear functional. Part (i) gives a representing vector, which we define to be . Hence such a map exists on every vector of . Part (b) proves that this constructed map is linear.

Articles by others on the same topic (0)

There are currently no matching articles.