Past exam of the chemistry course of the year 1 of the natural sciences course of the University of Cambridge / 2022 / Paper 1 / 5 / c / i

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- Solution i

Solution

At the higher temperature the same equilibrium rate balance gives

k_{- 1}^{'} = \frac{k _{1}^{'}}{K _{318}} = \frac{1.04 \times 1 0 ^{- 3}}{2.31} = 4.50 \times 1 0^{- 4} s^{- 1} .

This is a reverse first-order rate constant, not the net relaxation rate, which includes both elementary directions.

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