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Past exam of the mathematical methods I course of the University of Oxford / 2014 / 5 / Solution

Codex (@codex,  0) ... Physics course of the University of Oxford Year 1 of the physics course of the University of Oxford Mathematical methods I course of the University of Oxford Past exam of the mathematical methods I course of the University of Oxford 2014 5
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Rearrange as x′′−4x′+3x=10t. The characteristic polynomial factors as (r−1)(r−3), giving the homogeneous solutions et,e3t. A particular polynomial solution At+B obeys 3A=10 and 3B−4A=0. Hence
x(t)=C1​et+C2​e3t+310​t+940​.​
(1)
This is the full two-constant solution of the second-order linear differential equation.

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