OurBigBook About$ Donate
 Sign in Sign up

Past exam of the mathematics course of the University of Cambridge / 2010 / iii / Paper 36 / 1 / c / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2010 iii Paper 36 1 c
Created 2026-10-03 Updated 2026-10-14  0 By others on same topic  0 Discussions Create my own version
Conditional on the success probability, the count has binomial distribution. Integrating its likelihood under the uniform prior distribution, or equivalently a beta distribution with parameters (1,1), gives
p(y∣H1​)=∫01​(yn​)θy(1−θ)n−ydθ=(yn​)Γ(n+2)Γ(y+1)Γ(n−y+1)​=n+11​​,y=0,…,n.
(1)
The prior predictive distribution is therefore uniform over the possible counts. Excluding the single point θ=1/2 does not alter this integral because a continuous prior distribution gives that point zero probability. This calculation is the marginalization underlying Beta-binomial conjugacy.

 Ancestors (11)

  1. c
  2. 1
  3. Paper 36
  4. iii
  5. 2010
  6. Past exam of the mathematics course of the University of Cambridge
  7. Mathematics course of the University of Cambridge
  8. Course of the University of Cambridge
  9. University of Cambridge
  10. List of universities
  11.  Home

 View article source

 Discussion (0)

New discussion

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.
  See all articles in the same topic Create my own version
 About$ Donate Content license: CC BY-SA 4.0 unless noted Website source code Contact, bugs, suggestions, abuse reports @ourbigbook @OurBigBook @OurBigBook