Let be any positive integer. If divides and , it divides the integer linear combination . Conversely, if divides and , it divides . Thus and have exactly the same positive common divisors. Their greatest elements coincide:
This greatest common divisor invariance is the step behind the Euclidean algorithm; it does not require , although that additional bound ensures the algorithm terminates. If the convention permits , the same argument works and for .
The successive division with remainder steps of the Euclidean algorithm are
Each step preserves the greatest common divisor by part (a). The final nonzero remainder is , so
Back-substitute in the Euclidean algorithm to obtain an integer linear combination:
Multiplying by gives the particular solution of the linear Diophantine equation. Subtracting it from any other solution and dividing by gives
The integers and are coprime, so divides . Writing forces . Conversely these expressions satisfy the original equation for every integer . Thus all solutions of a linear Diophantine equation here are
Rearrange the polynomial equation as a fixed point equation:
First establish existence and uniqueness of the target root of a polynomial. Since is a continuous function, and , the intermediate value theorem gives a root of a polynomial . Moreover for all real , so is strictly increasing and this is its only real root of a polynomial.
For ,
so maps the closed interval into itself. Also
The mean value theorem therefore gives on the closed interval: is a contraction mapping. For any starting value , all iterates remain in that closed interval, and since ,
Thus the fixed-point iteration converges to the unique real root of a polynomial from every . This explicit error estimate proves the needed convergence directly.

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