Write , with because the triangle is nondegenerate. Let be its circumcenter. Equality of the complex modulus values gives . Equality of , after expanding the squares, gives
Thus the real part and imaginary part determine
Using the complex conjugate , we also have
Therefore
The nonzero denominator is exactly the nondegeneracy condition. If is real, the three distinct collinear points do not have a finite circumcenter.

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