Past exam of the MPhil in micro- and nanotechnology enterprise course of the University of Cambridge / 2019 / Paper 1 / Section B / 10 / iii / Solution

For two equal spheres, the Derjaguin approximation uses $R_{\mathrm{eff}}=R/2$. A planar nonretarded Van der Waals force interaction has energy per area $W(h)=-A_H/(12\pi h^2)$, soThe force is attractive, with magnitude $13.0\mu \mathrm{N}$, taking separation increase as positive. Using the sphere–plane value of $R_{\mathrm{eff}}$ would overestimate it by a factor of two. The gap is much smaller than either radius, as required. Treat the supplied Hamaker constant as the effective one for the intervening medium; roughness, solvation and molecular-scale contact can modify a literal $1\mathrm{nm}$ experiment.