When , the explicit amplification factor becomes
A single Fourier mode has constant modulus in space and is not in the l2 sequence space. Instead choose a whole interval of frequencies on which there is definite growth. Let
The inverse Fourier transform here gives the real sequence
By the Parseval identity, its squared norm is , finite and strictly positive. These data are also compatible with sampling a bounded continuous function: use
The value at zero is the limit of the displayed quotient, and .
On we have . Therefore the transformed solution and the Parseval identity give
For each fixed pair , take
Taking square roots proves for every . In particular the norm already increases at the first step, so no positive mesh pair gives practical stability in the contraction sense of (b).
The native PDF places the existence of before the universal quantifier over mesh pairs. If this means a single positive independent of , that assertion is false for nonzero data. Indeed, for every datum the same Fourier symbol gives
For any proposed fixed , choose . The upper bound then contradicts the requested lower bound at . The correct quantifiers are , with nonzero square-summable data as constructed above.
Finally, failure of this stronger practical stability of a finite difference scheme should not be confused with every possible refinement notion of numerical stability. If , then gives
Thus a finite-time mesh-uniform bound can hold under this severe refinement even though contraction fails on every positive mesh. This is the distinction recorded in centered-advection refinement-dependent stability.

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