Use . Fix . For small, all triples , , lie in a fixed compact set up to null sets. The continuous derivatives are uniformly continuous there, with a modulus as . The integral form of the mean-value expansion gives a remainder bounded by
The proposed linear derivative is bounded because its coefficient functions are bounded on that compact set. The remainder is little-oh of the norm, proving Fréchet differentiability and
The derivative only needs to exist almost everywhere; the uniform compact-range bound handles its measurable representative.

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