Past exam of the physics 1 paper of the University of Oxford / 2013 resit / 6 / a / Solution

The external work equals the change in relativistic kinetic energy, $W=m_e{c}^2({\gamma }_f-{\gamma }_i)$. With $m_e{c}^2=511\mathrm{keV}$,The rest energy cancels between endpoints. At these speeds, the nonrelativistic estimate $\frac{1}{2}{m}_e{c}^2(0.11^2-0.10^2)=0.53655\mathrm{keV}$ is close but slightly smaller.