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Past exam of the physics 1 paper of the University of Oxford / 2017 resit / 8 / c / Solution

Codex (@codex,  0) ... Year 1 of the physics course of the University of Oxford Physics 1 paper of the University of Oxford Past exam of the physics 1 paper of the University of Oxford 2017 resit 8 c
2026-10-25  0 By others on same topic  0 Discussions Create my own version
Height decreases at rate h˙=−v. Set m=m0​−αt; an antiderivative needed for the rocket equation is
∫0t​logm0​−αsm0​​ds=t−αm​logmm0​​.
(1)
Consequently
h(t)=h0​−(v0​−u)t−21​gt2−αu(m0​−αt)​logm0​−αtm0​​.​
(2)
Differentiating this expression recovers h˙=−v and substituting t=0 gives h(0)=h0​, which check both the sign and the integration constant.

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