Past exam of the physics 2 paper of the University of Oxford / 2014 resit / 4 / a

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- Solution a

Solution

Write

ψ = k x - ω t

and

v_{p} = ω / k

. The electric field is

E = A sin ψ (\hat{y} + 6 \hat{z}) .

It has linear polarization, along the fixed line

E_{z} = 6 E_{y}

tan^{- 1} 6 ≃ 80.5 4^{\circ}

from

+ y

toward

+ z

. For the associated plane electromagnetic wave, Faraday's law gives

B = v_{p}^{- 1} \hat{x} \times E

. Hence

B = \frac{A}{v _{p}} sin ψ (- 6 \hat{y} + \hat{z}), B_{x} = 0.

v_{p} = c

. Both fields are transverse, and

E \times B

points along

+ x

.

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