Gaudin's lemma is the projection kernel determinant integration identity. Suppose an integral kernel satisfies
with the relevant integrals absolutely convergent. Define and . Then
In particular, a finite-rank projection kernel of rank has .
One can see the factor directly from the permutation expansion of the determinant. Terms whose permutation fixes integrate to . Every permutation on the other indices admits insertions of into a cycle. Each insertion reverses its sign, and the reproducing identity contracts its two adjacent kernel factors into one. These terms integrate to , proving the formula.
The squared norm of in is , where . Choose positive normalizing constants
Then are an orthonormal set for Lebesgue measure. Expanding the finite sums gives
Thus this is an orthogonal polynomial projection kernel, explicitly
The positive constants above are forced by the reproducing identity: before normalization, its convolution multiplies each independent term by . Each multiplier must equal one. Changing the sign of a real leaves the kernel unchanged.
Use the symmetric joint probability density function of exchangeably labelled eigenvalues, normalized over all of . The finite-rank projection kernel has
Successive applications of Gaudin's lemma therefore give
It follows that
As a normalization check, the weighted Vandermonde determinant yields
If instead one uses ordered eigenvalues on , the normalized density on that chamber is six times the labelled density. In that convention the determinant prefactor on the chamber is one.

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