Gaudin's lemma is the projection kernel determinant integration identity. Suppose an integral kernel satisfieswith the relevant integrals absolutely convergent. Define and . ThenIn particular, a finite-rank projection kernel of rank has .
One can see the factor directly from the permutation expansion of the determinant. Terms whose permutation fixes integrate to . Every permutation on the other indices admits insertions of into a cycle. Each insertion reverses its sign, and the reproducing identity contracts its two adjacent kernel factors into one. These terms integrate to , proving the formula.
The squared norm of in is , where . Choose positive normalizing constantsThen are an orthonormal set for Lebesgue measure. Expanding the finite sums givesThus this is an orthogonal polynomial projection kernel, explicitlyThe positive constants above are forced by the reproducing identity: before normalization, its convolution multiplies each independent term by . Each multiplier must equal one. Changing the sign of a real leaves the kernel unchanged.
Use the symmetric joint probability density function of exchangeably labelled eigenvalues, normalized over all of . The finite-rank projection kernel hasSuccessive applications of Gaudin's lemma therefore giveIt follows thatAs a normalization check, the weighted Vandermonde determinant yieldsIf instead one uses ordered eigenvalues on , the normalized density on that chamber is six times the labelled density. In that convention the determinant prefactor on the chamber is one.
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