Assume the scalar potential is real, so the Weyl equation has a Hermitian Hamiltonian H=σ⋅p+V. Multiplying the equation and its adjoint by ψ† and ψ respectively givesThus with ρ=ψ†ψ and J=ψ†σψ, the lower-index four-current jμ=(ρ,−J) obeys ∂μjμ=0.
∂t(ψ†ψ)=−∇⋅(ψ†σψ).
For K=σ⋅p,Consequently K is conserved for spatially constant V; a spatially uniform time-dependent scalar offset would also commute with it. For general nonuniform V it is not conserved. At nonzero momentum, (σ⋅p^)2=I, so the helicity eigenvalues are +1,−1. In the chosen constant-potential Weyl Hamiltonian, the positive E−V branch has helicity +1; the negative branch has −1. An expectation value in a superposition need not itself be an eigenvalue.
[K,H]=[K,V]=−iσ⋅∇V.
For dependence on z alone and constant V0, remove the common phase by ψ=e−iV0tψ. Then ∂tψ=−σz∂zψ. The normalized eigenvectorsobey σzu±=±u±. The corresponding first-order transport equations have characteristics t−z and t+z, respectively, givingHere η propagates toward +z and ρ toward −z, both at unit speed.
u+=(10),u−=(01)
ψ(z,t)=e−iV0t[η(t−z)u++ρ(t+z)u−].
For a fixed unit vector n^, replace z by n^⋅x and choose orthonormal spinors satisfying (σ⋅n^)u±(n^)=±u±(n^). If n^=(sinϑcosφ,sinϑsinφ,cosϑ), one choice isIndependent constant phases on the spinors can be absorbed into the two arbitrary envelope functions.
u+(n^)=(cos(ϑ/2)eiφsin(ϑ/2)),u−(n^)=(−e−iφsin(ϑ/2)cos(ϑ/2)).
Evaluate the envelopes at their displayed arguments and set a=η∗ρ. The common phase e−iV0t cancels from every bilinear. Direct use of the Pauli matrices givesThe physical longitudinal current is Jz=∣η∣2−∣ρ∣2: the two density profiles move in opposite directions. Their separate transport identities give ∂t(∣η∣2+∣ρ∣2)+∂z(∣η∣2−∣ρ∣2)=0.
jμ=(∣η∣2+∣ρ∣2,−2Rea,−2Ima,∣ρ∣2−∣η∣2).
For a coherent superposition, the transverse currents Jx=2Re(η∗ρ) and Jy=2Im(η∗ρ) generally do not vanish. They are independent of x,y, so they contribute no divergence in this one-dimensional construction. Omitting them would give an incorrect local four-current. Pointwise, ∣J∣2=(∣η∣2+∣ρ∣2)2, so the pure two-component Weyl current is future null wherever the density is nonzero. If only one envelope is present, the current points entirely along its propagation direction; an incoherent average can remove the transverse interference terms.
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