Assume the companion is much less massive than the star, the sinusoid represents a circular Keplerian orbit, and the transit implies sini≃1. Ignore dilution, limb darkening and grazing geometry when estimating the radius. With P=5×86400s,The stellar reflex radial-velocity semi-amplitude gives K≃(m/M⊙)(2πa/P), while transit depth gives δ≃(Rp/R⊙)2. ThereforeThe mean density relative to the supplied Jupiter values isThis is a low-density hot gas giant. Strong irradiation can slow contraction or help sustain an inflated envelope; internal heating and a different heavy-element fraction are other possibilities. The inferred low mass also reduces gravitational compression. Mass and radius alone do not determine which inflation mechanism operates.
a≃(4π2GM⊙P2)1/3=8.56×109m=0.0572AU.
m≃1.12×1027kg=0.589MJup,Rp≃9.84×107m=1.408RJup.
ρˉJupρˉp≃1.40830.589=0.211,ρˉp≃2.80×102kgm−3.
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