Past exam of the short options paper shared by Prelims and Parts A and B of the physics course of the University of Oxford / 2017 / S16 / 1 / 4 / Solution

The ion density is $\rho /(9m_u)$ and double ionization gives $n_e\simeq 2.48\times 10^{29}$ m${}^{-3}$. Therefore $\hslash {\omega }_p\simeq 18.5$ eV. The photon energy loss gives $\hslash \omega =30$ eV, while momentum conservation givesInverting the stipulated dispersion law givesAn angular frequency expressed “in eV” means $\hslash \omega$, not the frequency itself. The temperature is a formal inference conditional on the dispersion model, whose validity is tested next.