Past exam of the short options paper shared by Prelims and Parts A and B of the physics course of the University of Oxford / 2017 / S3 / 1 / b

Table of contents
- Solution b

Solution

The emitted photon has energy

E_{3} - E_{2} = Ry (1/4 - 1/9) = 5 Ry /36

. Therefore

λ = \frac{36 h c}{5 Ry} ≃ 656 nm .

This is the Balmer-alpha transition in this approximation. Absorption in the reverse direction has the same photon energy; fine structure and radiative corrections are beyond the model.

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