For each random variable, the probability mass function gives
Let . By linearity of expectation and variance additivity for independent random variables,
The independence is needed for the variance calculation, but not for the mean.
Each has the same probability distribution as . By independence, the entire vector and its negative have the same joint law, so has a symmetric distribution about zero. The two disjoint tail events consequently have equal probabilities:
Apply Chebyshev's inequality with the mean and variance from (i):
Using only containment in the two-sided event would give ; the symmetry supplies the necessary extra factor .

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