Work over the field containing the stated distinct eigenvalues of ; in a real formulation these must be real to obtain real eigenvectors. Choose one eigenvector for each distinct eigenvalue. By independence of eigenvectors for distinct eigenvalues, these vectors are a basis. Consequently each eigenspace has dimension one: in an expansion in this eigenbasis, forces every coefficient with a different eigenvalue to vanish.
Now let be any eigenvector of . By part (d), belongs to its one-dimensional eigenspace, so for some scalar . This proves that is an eigenvector of , including the case , where . This is the crucial one-dimensional step in simple spectrum gives simultaneous diagonalization.

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