Rare-jump counterexample to a strong law with convergent first-moment averages ($\mathbb{P}(X_n=1\pm n)=1/(2n\log n),X_n\to 1\text{ in }{L}^1,n^{-1}{\sum }_{i=2}^{n+1}{X}_i\nrightarrow \text{ a finite limit a.s.}$)

Take independent random variables equal to $1+n$ and $1-n$ with probability $1/(2n\log n)$ each, and otherwise equal to one. Their first absolute deviations are $1/\log n\to 0$, so $X_n\to 1$ in L1 convergence. The same triangle-inequality argument gives convergence in $L^1$ of their arithmetic averages to one. For $p>1$, however, $\mathbb{E}|X_n-1{|}^p=n^{p-1}/\log n\to \infty$.

The exceptional jumps occur infinitely often almost surely by the Borel-Cantelli second lemma, since $\sum 1/(n\log n)=\infty$. If the arithmetic averages $S_n/n$ converged to any finite value along a sample path, then $X_{n+1}/n=S_n/n-[(n-1)/n][S_{n-1}/(n-1)]$ would tend to zero. At each exceptional jump its magnitude is at least one. Thus the averages have no finite almost sure limit. Independence and convergence of first-moment averages do not alone give a strong law of large numbers.