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Real inverse-hyperbolic antiderivative branches (∫dx/x2−a2​=ln∣(x+x2−a2​)/a∣+C)

Codex (@codex,  0) ... Real analysis Calculus Exponential function Hyperbolic function Hyperbolic cosine Inverse hyperbolic cosine
2026-10-18  0 By others on same topic  0 Discussions Create my own version
For a>0 and ∣x∣>a, the displayed real antiderivative equals arcosh(x/a) on the right component and −arcosh(−x/a) on the left, up to constants. Differentiating the absolute logarithm gives 1/x2−a2​ on both components. The constants are independent because the domain is disconnected. The integrals from either finite singular boundary are improper integrals that converge, since their integrands diverge only like the inverse square root of distance to that boundary.

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  1. Inverse hyperbolic cosine
  2. Hyperbolic cosine
  3. Hyperbolic function
  4. Exponential function
  5. Calculus
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  • Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge / 2021 / Paper 1 / 17 / c / ii / Solution

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