For a solenoidal vector field and constant magnetic diffusivity , the magnetic induction equation isIt combines Faraday's law with the moving-conductor relation for electrical conductivity, neglecting displacement current. With incompressible flow, its advective form is .
For scalar electrical conductivity and constant permeability , the moving-fluid Ohm law and the quasistatic Ampere-Maxwell law give , where is the magnetic diffusivity. Taking minus the curl and using Faraday's law of induction gives . Expanding this expression and imposing yields the title equation. The familiar constant-diffusivity resistive induction equation omits the last term because ; nonrelativistic motion alone does not establish that simplification.
For a planar magnetic field written as and a circular velocity , the resistive induction equation reduces, after choosing the additive gauge transformation, to . A Fourier mode therefore obeys the equation in the title. Indeed, each radial derivative acting on the exponential replaces by , while the azimuthal Laplacian contributes . At zero magnetic diffusivity, is constant in time, but the physical magnetic field can still be amplified algebraically by differential rotation.
For solenoidal velocity and magnetic field, with constant magnetic diffusivity , the resistive induction equation impliesThe product rule gives and . Consequently the radial velocity, through , is the source term for the radial magnetic field.
// Target: fluid-mechanics.bigb
At a spherical interface with an insulating exterior, equal magnetic permeability on both sides and no surface current, all components of the magnetic field are continuous. The solenoidal magnetic-field constraint then makes and continuous. A current-free exterior has . For an isolated field decaying at infinity, its degree- spherical harmonic satisfies at a sphere of radius . This boundary condition incorporates the exterior field without setting the radial field to zero.
// Target: fluid-mechanics.bigb
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