Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 316 3 iii Solution Created 2026-09-24 Updated 2026-09-25
Insert the planets' two secular eigenmodes and define their forcing strengthsSolving the first-order linear ordinary differential equation givesThe first term is the particle's freely precessing eccentricity. The remaining terms are its forced eccentricity, phase-locked to the planets' modes. In the complex plane, their vector sum makes the eccentricity and longitude of periapsis oscillate. A denominator becomes small at a secular resonance ; the nonresonant formula then ceases to be uniform.
Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 316 3 iv Solution Created 2026-09-24 Updated 2026-09-25
The free precession rate tends to zero far inside the inner planet, diverges on approaching , diverges on both sides of , and tends to zero far outside the outer planet. Between and it diverges at both ends and has at least one minimum. A horizontal line therefore crosses once inside and once outside , plus zero, one tangent, or two times between the planets. There are consequentlylocations of the corresponding secular resonance. This argument uses the smooth Laplace-Lagrange secular theory away from the immediate neighborhoods of the planets and from mean-motion resonances.
Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 316 3 vi Solution Created 2026-09-24 Updated 2026-09-25