Enolization 2026-10-20
Interconversion of a carbonyl compound with its enol or enolate-derived forms. Reprotonation of a planar intermediate can epimerize an alpha stereocentre.
For a concrete choice, draw the intermediate in the planar ring orientation used in the question and put the allylic OH on the upper face, with a solid-wedge C-OH bond. Fix either configuration at the R-bearing and methoxy-bearing centres and retain it throughout; no absolute configuration is specified by the question.
Draw the six-membered rearrangement array with its allylic C-C-C segment along the same ring edge and the O-ketene-acetal tether above that edge. Suprafacial transfer forms the new ring-carbon–CHCOEt bond on that upper face: draw it as a solid wedge, replacing the original allylic OH with the shifted double bond. The R-bearing and methoxy-bearing stereocentres retain their configurations. The opposite OH epimer transfers the tether from the opposite face and gives the opposite new stereocentre. Favor the chair-like transition structure that puts the larger tether substituents outward. This explicitly correlates the selected OH face with the new bond rather than invoking a freely rotating allylic carbocation.
No stereochemical information need survive from the starting carbinol. Ionization converts that tetrahedral stereocentre into a planar, delocalized propargyl/allenyl cation before cyclization. In achiral conditions the two enantiomeric pathways to the new stereocentre in the tert-butyl-derived product are equivalent, so an enantiopure alcohol is expected to give racemic product. A claim of retained enantiopurity would require evidence for unusually effective conformational memory or ion-pair control.
A hydroxyl-directed Evans–Saksena reduction gives the required anti-1,3-diol. A suitable reagent is tetramethylammonium triacetoxyborohydride in an acidic medium, for example acetic acid/acetonitrile. Ligand exchange between the pre-existing alcohol and an acetoxyborohydride group tethers the reducing reagent to the substrate. Intramolecular hydride delivery to the ketone then proceeds through a six-membered arrangement, converting C=O to an alkoxide while conserving all existing stereocentres. Hydrolysis releases the second hydroxyl group.
The preferred directed transition-state conformation minimizes crowding by the larger carbon-chain substituents. It delivers the new C–H bond on the face that leaves the two hydroxyl groups anti, as in B: with the original hydroxyl drawn as a wedge in the printed zigzag, the new hydroxyl is dashed. The intervening methyl stereocentre is retained. Choosing an undirected borohydride reduction would not by itself rationalize this strong substrate-controlled relationship.
The free allylic hydroxyl can hydrogen-bond to the peracid and accelerate directed oxygen transfer to the nearby double bond. The remote styryl double bond lacks this directing contact. Epoxidation of the hydroxyl-adjacent alkene is therefore favoured, even though both alkenes are in principle oxidizable. Peracid epoxidation is a concerted oxygen transfer: alkene donation to terminal peroxide oxygen, O–O cleavage, proton transfer and carbonyl re-formation occur through a cyclic transition-state arrangement. The alkene's E geometry is retained as a trans relationship between its substituents in the epoxide.
The two alkene faces are diastereotopic because the molecule already contains stereocentres. A plausible substrate-controlled conformation minimizes allylic strain and presents the face opposite the bulky OTBS-bearing part of the chain to the oxidant. Predict epoxide oxygen on the face opposite OTBS, retaining the pre-existing methyl and OTBS configurations. Hydrogen-bond direction, steric approach and conformational population compete; one cannot deduce an exact diastereomeric ratio from the flat drawing alone. The same facial preference has been discussed for this synthetic series.[ref]
The acetylide attacks the less substituted terminal epoxide carbon by SN2 ring opening. The C–O bond at that carbon breaks, leaving the oxygen attached to the original substituted stereocentre. Protonation gives . Dissolving-metal reduction then gives the E alkene and also cleaves the benzyl ether.
Thus H is with an E double bond, and its original epoxide-derived stereocentre is retained geometrically. No new tetrahedral stereocentre is formed: the attacked epoxide carbon becomes CH. The new stereochemical information is the E alkene geometry. Calling its secondary hydroxyl carbon “newly generated” would confuse changing its functional environment with creating a new stereocentre.
The secondary alcohol of H condenses with the aldehyde under acid catalysis to form a hemiacetal, then loses water to an oxocarbenium ion. Its tethered E alkene attacks the aldehyde-derived carbon through a chair-like six-membered arrangement: the alkene carbon farther from the alcohol forms the new C–C bond, placing a carbocation at the nearer alkene carbon. Trifluoroacetate captures that cation; the basic methanolic work-up cleaves the trifluoroacetate ester to reveal the ring hydroxyl group. This is a Prins cyclization.
Number the product ring from oxygen through the aldehyde-derived carbon as C2, then the alkene-derived methyl-bearing carbon C3, the hydroxyl-bearing carbon C4, the intervening methylene C5 and the original alcohol carbon C6. A chair keeping the bulky C2 side chain and C6 hydroxymethyl group equatorial predicts 2,6-cis substitution. Suprafacial alkene capture preserves the E-alkene-derived relationship, giving 2,3-trans between the C2 side chain and C3 methyl. Preferred equatorial trapping of the C4 cation gives 3,4-trans, hence the 2,4,6-cis arrangement of the substituent-bearing bonds in the favoured chair. In the printed flat-ring orientation, draw the C2 side chain, C4 hydroxyl and C6 hydroxymethyl behind the plane, and C3 methyl in front. Existing stereocentres in the aldehyde side chain and at C6 are retained; they anchor the absolute face of this assignment.
Figure 1.
Original product connectivity and stereochemical models for the directed reductions, aldol and Prins steps
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A consistent proposed sequence is desilylation, five-membered hemiketal formation, retro hetero-Diels–Alder opening, intramolecular aldol addition and hemiacetal closure. The essential carbon rearrangement is loss of the original ketone–side-chain bond and formation of a bond between its two neighbouring carbons; it is not a simple Michael addition.
For an explicit atom map, label the starting six-membered ring , with the ketone at , methyl substituents at and , the hydroxy group at , and the side chain . Here is the methylene and is the carbon bearing the protected alcohol. Let be the original ketone oxygen and the protected alcohol oxygen. These labels identify atoms, not new substituents.
First, Fluoride removes the silyl protecting group from . The resulting alcohol attacks the protonated ketone at , forming the five-membered hemiketal . The original oxygen is now a hydroxy group; the original pyran ring remains intact at this stage.
Next, The original pyran ring can undergo a retro hetero-Diels-Alder reaction. The three electron-pair movements are , and : break and , and form the three indicated double bonds. The result is the tethered aldehyde/dienol ester
The temporary bond keeps both reacting ends within the same molecule. At , both oxygen substituents remain attached, and the new tether prevents separation into independent fragments.
Then The enol attacks the tethered aldehyde at . Formation of , restoration of , and proton transfer give the six-membered lactone ring , with . This is an intramolecular aldol reaction, and it supplies the crucial new carbon–carbon bond without losing any carbon atom.
Finally, Keto-enol tautomerism at gives the methyl ketone at and introduces the hydrogen at . The alcohol then attacks that ketone, closing the five-membered hemiacetal ring . The resulting fused rings have exactly the product's connectivity: is the lactone carbonyl, is its ring oxygen, and is the five-membered-ring oxygen.
The stereocentre at survives throughout this sequence. The configuration initially at is erased at the aldehyde stage, and those at , , and arise during the later cyclization and proton-transfer steps. A folded intramolecular aldol reaction followed by reversible hemiacetal formation is consistent with the drawn cis ring junction, but connectivity and orbital bookkeeping alone do not prove that it is the unique selected diastereomer. In particular, a claim of simple retention at would contradict this atom map.
A related pyranone-to-fused-lactone rearrangement under aqueous hydrogen fluoride is experimentally reported; that account also explicitly qualifies the relative stereochemistry as assigned on mechanistic grounds. The sequence above is a proposed explanation of the examination structure, rather than a mechanism claimed to have been experimentally established in that paper.[ref]
Both free primary allylic alcohols undergo Sharpless asymmetric epoxidation. With slightly more than two equivalents of hydroperoxide, the expected fully oxidized product is the diepoxide, with both original C=C bonds converted to epoxides and both primary alcohols retained. The two central pre-existing stereocentres and their ether substituents are retained.
The stereochemical construction is unambiguous by applying the L-(+)-tartrate mnemonic separately at each end: orient that alkene horizontally with its CHOH group at lower right, and deliver oxygen from the back face. In the source's original in-plane orientation this gives the left epoxide oxygen behind the plane and the right epoxide oxygen in front. The methyl and hydroxymethyl groups retain their original relative arrangement about each former double bond. One cannot simply draw both oxygens on the same face of the original extended chain: the two allylic-alcohol ends have opposite drawing orientations. titanium binding to each free hydroxyl directs oxygen transfer; the pre-existing stereocentres can create matched/mismatched rate differences, but the stated reagent control predicts the stereochemistry of both epoxidations. Molecular sieves maintain a dry active titanium–tartrate system.[ref]
Figure 1.
Original facial-selectivity and axial-projection solution models
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An unsaturated Rh(I)–BINAP complex undergoes oxidative addition of the aldehydic C–H bond, giving a Rh(III) acyl hydride. Coordination of the tethered alkene brings it into the chiral coordination sphere. hydride migration to the internal, tert-butyl-substituted alkene carbon places Rh on the terminal methylene. The resulting acyl–alkyl complex has the connectivity required for a five-membered ring. reductive elimination between its acyl and alkyl carbons closes the C–C bond, releases the cyclopentanone and regenerates Rh(I).
The aldehyde carbon becomes the ketone carbonyl carbon; its hydrogen ultimately reaches the alkene-derived internal carbon. The original tert-butyl substituent remains attached to the internal alkene carbon, which becomes the beta stereocentre of the cyclopentanone. alkene coordination and insertion favour the chiral pocket arrangement with the bulky tert-butyl group in the less crowded region of the BINAP complex. For the stated (S)-BINAP system the observed product is the beta-tert-butylcyclopentanone, equivalently the product with tert-butyl on the solid-wedge face in the supplied ring orientation. Its priorities are tert-butyl, the shorter carbonyl-side ring path, the other ring path, and hydrogen. The ligand's S label alone is not a general rule that every product stereocentre must be S; the substrate orientation in the catalyst must also be specified. No decarbonylation is needed in the productive hydroacylation cycle.
The free allylic alcohol directs epoxidation of the adjacent alkene rather than the remote double bond. Applying the D-(−)-tartrate mnemonic gives the epoxide oxygen on the back face in the source orientation, with both new C–O bonds dashed if the original six-membered ring is kept in the plane. The CHOH substituent at the lower epoxide carbon consequently projects towards the front in an explicit tetrahedral product drawing. The remote double bond is retained. The opposite tartrate would reverse both newly created epoxide stereocentres; it would not alter the location of the epoxidized alkene.
The secondary hydroxylamine condenses with formaldehyde. nitrogen attacks the carbonyl carbon, giving a carbinolamine; proton transfer and loss of water generate the tethered nitrone , where is the entire bicyclic substituent attached to nitrogen in D. Molecular sieves remove water, favouring this condensation.
The nitrone undergoes an intramolecular 1,3-dipolar cycloaddition with the retained cyclohexene double bond. To define E precisely, label the former oxime carbon , the adjacent upper ring junction , the other junction , and the alkene carbons and such that the chain from to the more remote alkene terminus is . Let be the new formaldehyde-derived nitrone methylene. The cycloaddition forms and O–, retains N–O and N–, and changes N= and into single bonds. The new five-membered heterocycle is N––––O. These connections, together with the original bicycle, specify the bridged isoxazolidine E.
The inwardly tethered cycloaddition is suprafacial at the alkene and preserves the existing carbon stereocentres; the C–C and C–O additions occur on the same accessible alkene face. The pre-existing N-substituent orientation restricts which fold can bring both reacting ends together without crossing the bridge. This is a genuine two-new-bond cycloaddition, not a Mannich reaction followed by unrelated oxygenation.
Figure 1.
Original atom-labelled connectivity model of the nitrone cycloaddition product E
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