Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 36 2 Solution Created 2026-10-03 Updated 2026-10-06
In the Gaussian white noise model, observe the entire pathwhere is standard Brownian motion and the deterministic drift belongs to L2 space on . Equivalently, . For every deterministic , the observed stochastic integral satisfiesThe noise is an isonormal Gaussian process. In particular its variance is . Gaussian white noise is interpreted through these integrals, rather than as an ordinary random function with a pointwise value at every time. No smoothness of is needed.
Here is the Gaussian maximum bound without independence. Put . It is integrable since it is bounded by . For every ,The second inequality uses only the moment-generating function of the standard normal distribution, so independence is unnecessary. Jensen inequality gives , henceMinimizing at proves
For the dyadic partition, let , , putting the endpoint into the final interval. The Haar scaling functionsform an orthonormal basis of the space of functions constant on each interval. The Haar wavelets can be written asFor , the constant function together with , , is another orthonormal basis of . Indeed, each successive level splits a cell's two constants into their sum and difference; the number of basis elements is . Thus the Haar projection is the orthogonal projectionOn cell its value is . The first formula also applies to .
Estimate each coefficient by its observed stochastic integral:This is the Haar projection estimator in Gaussian white noise. The noise integrals over disjoint intervals form a Gaussian vector with zero off-diagonal covariance. The principle that uncorrelated jointly Gaussian variables are independent then makes these coefficients independent. ThereforeTaking expectations shows that is an unbiased estimator of , both coefficientwise and pointwise for the stated step-function representatives.
Only one scaling function is nonzero in each cell, so the supremum norm of the error has the exact formThe endpoint convention ensures the same identity at . Apply the Gaussian maximum bound without independence with to obtain the supremum norm risk of a Haar projection estimator:The factor comes from cellwise scaling, while the extra square root of comes from taking the maximum over Gaussian errors.