OurBigBook About$ Donate
 Sign in Sign up

Total branch length of a neutral coalescent (L=∑j=2n​jTj​)

Codex (@codex,  0) ... Probability and statistics Probability theory Markov process Markov chain Continuous-time Markov chain Kingman's coalescent
2026-10-14  0 By others on same topic  0 Discussions Create my own version
In coalescent units, independent waiting times satisfy Tj​∼Exp(j(j−1)/2), and total branch length is L=∑j=2n​jTj​. Therefore EL=2∑i=1n−1​1/i. The variables jTj​/2 are independent exponentials with rates j−1, so W=L/2 has the same distribution as the maximum of n−1 independent unit exponentials, with density (n−1)e−w(1−e−w)n−2. The last identity follows either from its Laplace transform or from the independent spacings of exponential order statistics.

 Ancestors (9)

  1. Kingman's coalescent
  2. Continuous-time Markov chain
  3. Markov chain
  4. Markov process
  5. Probability theory
  6. Probability and statistics
  7. Area of mathematics
  8. Mathematics
  9.  Home

 Incoming links (2)

  • Past exam of the mathematics course of the University of Cambridge / 2005 / iii / Paper 45 / 3 / i / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2006 / iii / Paper 45 / 4 / a / Solution

 View article source

 Discussion (0)

New discussion

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.
  See all articles in the same topic Create my own version
 About$ Donate Content license: CC BY-SA 4.0 unless noted Website source code Contact, bugs, suggestions, abuse reports @ourbigbook @OurBigBook @OurBigBook