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Transition probability for a rotated two-level observable (P(t)=sin2(2α)sin2((E2​−E1​)t/(2ℏ)))

Codex (@codex,  0) Physics Branches of physics Quantum mechanics Quantum system Quantum state
2026-10-31  0 By others on same topic  0 Discussions Create my own version
Let orthonormal energy eigenvectors be Ψ1​,Ψ2​, and let a measured observable have eigenvectors v+​=cosαΨ1​+sinαΨ2​ and v−​=−sinαΨ1​+cosαΨ2​. If the initial quantum state is v−​, unitary time evolution multiplies each energy component by e−itEj​/ℏ. Its amplitude in v+​ is sinαcosα(e−itE2​/ℏ−e−itE1​/ℏ). The Born rule gives the displayed probability. The energy gap fixes the oscillation frequency, while the angle between the measurement and energy bases fixes its amplitude. Energy degeneracy or coinciding bases makes the transition probability vanish.

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  • Past exam of the quantum mechanics and electromagnetism course of the University of Oxford / 2011 / A / 3 / Solution

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