What you would see the moving rod look like on a photo of a length contraction experiment, as opposed as using two locally measured separate spacetime events to measure its length.
Behavior fully described by quantum electrodynamics.
A single exponential map is not enough to recover a simple Lie group from its algebra Updated 2025-04-05 +Created 1970-01-01
Example at: Lie Groups, Physics, and Geometry by Robert Gilmore (2008) Chapter 7 "EXPonentiation".
TODO evaluate. No
pip install
???www.tudogostoso.com.br/receita/3468-bolo-de-fuba-cremoso.html
- December 2023:Turned out very good.
- replacements:
- used 3 soy milk + 1 milk cup instead of 4 milk
- salted butter rather than margarine
- 1 cup of sugar rather than 3, because OMG 3 cups of sugar for 4 cups of milk is insane, Brazil!
- replacements:
Some sources say that this is just the part that says that the norm of a function is the same as the norm of its Fourier transform.
Others say that this theorem actually says that the Fourier transform is bijective.
The comment at math.stackexchange.com/questions/446870/bijectiveness-injectiveness-and-surjectiveness-of-fourier-transformation-define/1235725#1235725 may be of interest, it says that the bijection statement is an easy consequence from the norm one, thus the confusion.
TODO does it require it to be in as well? Wikipedia en.wikipedia.org/w/index.php?title=Plancherel_theorem&oldid=987110841 says yes, but courses.maths.ox.ac.uk/node/view_material/53981 does not mention it.
In leanpub you write your book in a markdown variant they call Markua, marketed as "markdown for books".
TODO is there a reference implementation that runs locally for HTML output? Or the only reference implementation is closed under leanpub?
Spec: markua.com/
This is a good first concrete example of a Lie algebra. Shown at Lie Groups, Physics, and Geometry by Robert Gilmore (2008) Chapter 4.2 "How to linearize a Lie Group" has an example.
Every element with this parametrization has determinant 1:Furthermore, any element can be reached, because by independently settting , and , , and can have any value, and once those three are set, is fixed by the determinant.
To find the elements of the Lie algebra, we evaluate the derivative on each parameter at 0:
Remembering that the Lie bracket of a matrix Lie group is really simple, we can then observe the following Lie bracket relations between them:
One key thing to note is that the specific matrices , and are not really fundamental: we could easily have had different matrices if we had chosen any other parametrization of the group.
TODO confirm: however, no matter which parametrization we choose, the Lie bracket relations between the three elements would always be the same, since it is the number of elements, and the definition of the Lie bracket, that is truly fundamental.
Lie Groups, Physics, and Geometry by Robert Gilmore (2008) Chapter 4.2 "How to linearize a Lie Group" then calculates the exponential map of the vector as:with:
TODO now the natural question is: can we cover the entire Lie group with this exponential? Lie Groups, Physics, and Geometry by Robert Gilmore (2008) Chapter 7 "EXPonentiation" explains why not.
Given the function :the operator can be written in Planck units as:often written without function arguments as:Note how this looks just like the Laplacian in Einstein notation, since the d'Alembert operator is just a generalization of the laplace operator to Minkowski space.
LaTeX subset that output nicely to HTML.
Too insane though due to LaTeX roots, better just move to newer HTML-first markups like OurBigBook Markup or markdown.
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