 Glycolysis carbon and ATP ledger

Follow one glucose through canonical glycolysis, with no diversion of intermediates into other metabolic pathways. The investment stage uses two ATP to prepare the six-carbon substrate. Cleavage and rearrangement provide two glyceraldehyde 3-phosphate molecules, each containing three carbon chemical atoms. Each then yields one three-carbon pyruvate, one NADH, and two ATP in the payoff stage.^[ref]

The material check is $6=2\times 3$: all six carbon chemical atoms remain in the two pyruvates. No carbon dioxide has been released within this boundary. In the ATP ledger, each three-carbon route contains two ATP-forming transfers, soThe first pair of payoff transfers only restores the initial ATP inventory; the second pair creates the net gain. Four newly formed ATP is therefore compatible with only two additional ATP remaining.

For an original scaled example, stipulate complete conversion of $5\mu \mathrm{mol}$ of glucose. The initial $30\mu \mathrm{mol}$ of carbon chemical atoms becomes $10\mu \mathrm{mol}$ of pyruvate, still containing $30\mu \mathrm{mol}$ of carbon chemical atoms. The pathway spends $10\mu \mathrm{mol}$ of ATP, forms $20\mu \mathrm{mol}$ of ATP, and adds $10\mu \mathrm{mol}$ to the ATP inventory before any other ATP use. It also reduces $10\mu \mathrm{mol}$ of NAD+. These are calculated ideal amounts, not observed yields; side routes or incomplete conversion change the outcome.

A common biochemical net chemical equation isHere ${\mathrm{P}}_i$ is inorganic phosphate. The names group biochemical protonation and metal-binding states; the displayed proton and water terms use a common shorthand rather than a unique specification of every chemical species. The robust ledger records two net ADP-to-ATP conversions and two NAD+-to-NADH conversions. Summing the individual chemical equations cancels two invested ATP against four formed ATP and cancels the internal substrates, giving those coefficients.