 Nuclear pore transport balance

Nuclear accumulation should compare concentrations, not just total cargo. In an original constructed example, a cell nucleus occupies one volume unit and the accessible cytosol occupies nine. Of $130$ tracer units, $40$ are nuclear and $90$ are cytosolic. With $n_n,n_c$ the amounts and $V_n,V_c$ the accessible volume, the concentration ratio isOnly $40/130=4/13\approx 30.8\%$ of the cargo is nuclear, yet nuclear concentration is four times cytosolic concentration. A majority outside the cell nucleus does not rule out nuclear enrichment.

For comparison, freely exchanging nonbinding cargo at equal concentrations would have $n_n=13,n_c=117$: the nuclear fraction would equal the nuclear fraction of accessible volume, $1/10$. These are constructed amounts, not measurements from the nuclear pore localization experiment. Binding, unequal recovery or cargo degradation would require additional accounting before interpreting an assay.

A minimal two-compartment ordinary differential equation makes the distinction precise. Assume fixed accessible volume, no synthesis or degradation, and effective first-order exchange rates $a,b>0$:Total cargo $N=n_n+n_c$ is conserved. Setting the derivative to zero givesFor symmetric passive exchange with conductance $P$, $a=P/V_c$ and $b=P/V_n$, so the concentration ratio is one even when the amounts differ. Choosing instead $a=4/9$ and $b=1$ in reciprocal model-time units gives $n_n^{\ast }=40$ for $N=130,V_n=1,V_c=9$. The exact ordinary differential equation solution isSubstitution verifies the solution, and $a+b>0$ makes departures decay. This effective model can describe an asymmetric exchange balance, but does not by itself identify a nuclear localization sequence, transport receptor or source of energy.

The usefulness of the nuclear pore complex is precisely this combination of separation and exchange: a cell nucleus can maintain a distinctive protein population while receiving new cargo and exporting RNA. The nuclear pore localization experiment asks what feature controls entry; the nuclear pore transport balance asks what an accumulation readout actually means.