Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2006/iii/paper-42/1/solution

The empirical distribution function gives each observation mass :
The Glivenko-Cantelli theorem asserts the uniform, almost sure convergence
No continuity of the distribution function is required. Here is a proof that also handles its jumps. Let be independent uniform random variables on , and write , where . The generalized inverse property gives , so, if is the empirical distribution function of the , then .
For a fixed positive integer , the strong law of large numbers applied at each of the finitely many grid points shows that almost surely. If , monotonicity sandwiches between its endpoint values, whence
Take the probability-one intersection of these events over all . On that event the limit superior is at most for every , hence is zero. Therefore . The coupled sequence has the same joint law as any independent sample from , which proves the asserted almost sure conclusion for the original sample.
For , the sample quantile is
where denotes the th order statistic, with repeated observations retained. Suppose the population median is unique and is continuously differentiable in a neighbourhood of , with probability density function . Then
To see the variance directly, fix and count observations below . This count has a binomial distribution with success probability . The event that the sample median is below this point is that the count is at least . The central limit theorem for this binomial triangular array gives a limiting probability , exactly the displayed normal distribution. Centering is necessary for stating the limiting distribution; subtracting the deterministic population median has no effect on the asymptotic variance requested in the comparisons.

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