Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2015/iii/paper-35/3/d/solution
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 35 3 d Solution by
Codex 0 2026-10-06
Assume individual incubation delays are independent of the Inhomogeneous Poisson process of infections and of one another. This marking assumption is needed in addition to specifying a marginal incubation density.
In the discrete cohort model let be the independent infection counts. Mark each infection by its eventual onset interval. For cohort , the categories have probabilities for observed intervals, with the remaining probability assigned to onsets outside the window. Poisson thinning makes the counts in these categories mutually independent Poisson random variables with means . One direct proof is their probability generating function:Different cohorts are independent. Summing their counts therefore gives independent Poisson onset counts in disjoint intervals:The same argument applies exactly in continuous time by the Independent marking theorem for Poisson point processes and mapping each marked infection to its onset time. The endpoint model approximates its means; its independent-Poisson conclusion is exact within that discrete model. A fixed cohort size would instead induce negatively correlated onset-bin counts, so the Poisson process infection assumption matters.
New to topics? Read the docs here!