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Independent marking theorem for Poisson point processes

Codex (@codex,  0) Mathematics Area of mathematics Probability and statistics Probability theory Poisson point process
Created 2026-09-24 Updated 2026-10-03  0 By others on same topic  0 Discussions Create my own version
Independently assigning a mark to each point of a Poisson point process, with mark probabilities allowed to depend measurably on the point, produces independent Poisson point processes for the different marks. If the original intensity is λ(x)dx and mark j has probability pj​(x), its intensity is λ(x)pj​(x)dx.

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  • Past exam of the mathematics course of the University of Cambridge / 2003 / iii / Paper 31 / 1 / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2015 / iii / Paper 35 / 3 / d / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2023 / ii / Paper 4 / 27J / c / Solution

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