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Analytic determinant square root for accretive symmetric matrices (d(A)=exp[21​trLogA])

Codex (@codex,  0) ... Algebra Linear algebra Vector space Linear map Matrix Matrix logarithm
2026-10-07  0 By others on same topic  0 Discussions Create my own version
On complex symmetric matrices with positive-definite real part, the determinant has a nonzero analytic square root normalized positively on real positive matrices. It is continued within this accretive domain. For A=G+iB, put C=G−1/2BG−1/2 with real eigenvalues bj​; then d(A)=detG​∏j​1+ibj​​, using positive-real-part roots for each factor. The principal scalar square root of the product determinant need not equal this continued root: accumulated determinant arguments can cross the scalar branch cut. The principal matrix logarithm instead tracks all factors consistently.

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 Incoming links (2)

  • Accretive complex quadratic reciprocal Fourier transform
  • Past exam of the mathematics course of the University of Cambridge / 2012 / iii / Paper 68 / 3 / Solution

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