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Gravitational acceleration is the acceleration of a test particle in free fall in a Newtonian gravitational field. It is a vector pointing along that field; $g$ commonly denotes its positive magnitude. Near Earth's surface, the magnitude is approximately constant over shallow vertical scales. For a fixed spherical source it instead varies as $g(r)=\mu /r^2$, where $\mu$ is the standard gravitational parameter.

This is distinct from gravitational weight, the force $m\mathbf{g}$, and from apparent weight, the support force a scale measures. An orbiting body can have substantial gravitational acceleration while its apparent weight is zero.

A normal force is a contact force perpendicular to the constraining surface. It supplies support without being identical to gravitational weight: its magnitude depends on the other forces and the body's acceleration. For a body at rest on a horizontal scale with no other vertical forces, it equals $mg$. A freely falling body has no supporting normal force, despite its nonzero gravitational weight; this distinction defines the scale's apparent weight.

The volume $V$ is the three-dimensional space occupied by the body. Its mass $m$ measures its inertia: in Newtonian mechanics the resultant force is $m\mathbf{a}$. Its gravitational weight is the force exerted on it by gravity,For a uniform body, $m=\rho V$, where $\rho$ is its mass density; more generally $m=\int \rho dV$. Volume can change with temperature or pressure while the body's mass remains fixed in the classical closed-system model. Equal volumes of different materials need not have equal masses.

The same mass need not have the same gravitational weight. The local gravitational acceleration changes between planets and with position on Earth. Outside a spherical Earth, $g(r)=G{M}_{\oplus }/r^2$, so increasing altitude reduces it. Earth's rotation and shape also affect terrestrial weighing: a scale at rest on the rotating Earth responds to the effective acceleration including the centrifugal contribution, rather than simply to a spherical gravitational field.

Distinguish gravitational weight from apparent weight. A supporting scale measures a contact force. In a vertically accelerating cabin, upward acceleration $b$ gives $N=m(g+b)$ while contact is maintained. During common free fall, $N=0$ although $mg$ remains nonzero. Immersion in a fluid can similarly reduce the support needed through buoyancy, without removing the gravitational attraction. These distinctions explain why a change in a balance reading is not automatically a change of mass.

Weightlessness is the absence of supporting or constraining forces that would give a body an apparent weight. It does not require zero gravitational acceleration. A freely falling cabin and a small freely falling object inside share the same acceleration in a uniform field, so neither needs to support the other.

The circular orbit as continuous free fall gives a sustained example. Real spacecraft have small residual relative accelerations from tidal forces, atmospheric drag force and onboard disturbances; the ideal common-fall explanation does not assert that every point in an extended spacecraft experiences exactly the same Newtonian gravitational field. ^[ref]