In a parallel-plate rheometer, a point at radius on the upper plate moves at speed . The thin-gap approximation therefore gives the local shear rate
Define the rim value
An annulus of radius and width has area ; its tangential force is , and its moment arm is . The measured torque is consequently
For a generalized Newtonian fluid, . Changing the integration variable from to gives
Thus the requested kernel is
Multiplying by and taking a derivative with respect to turns the upper-limit contribution of the integral into the rim viscosity:
Therefore
A measured torque curve and its slope hence determine over the range of imposed rim shear rates.
The experimental law implies
Substitution gives
The graph is a decreasing rectangular hyperbola with a positive high-rate plateau and a divergence at the origin. Equivalently,
so the inferred material is a Bingham plastic with yield stress .
Let measure distance through the thin Bingham plastic layer, with a stationary wall at and large-scale velocity at . To leading lubrication order the shear stress is uniform across the layer. If , the material is unyielded and the no-slip wall makes the entire layer stationary. After yield,
Integrating across the depth gives the Bingham sliding law
Equivalently, for nonzero sliding,
Define the viscous number
The pressure relation gives
Using , the shear stress at imposed pressure is
The material therefore behaves as a pressure-dependent Bingham plastic with yield stress , while its steady concentration dilates as shear rate increases.
After a step in shear rate, the particles must rearrange and undergo shear-induced dilation or compaction. Because the sample is saturated, that volume change requires pore fluid to migrate through the packing, so pore pressure and effective particle pressure relax over a finite poro-viscous time. Measuring the transient stress can therefore constrain the permeability, and with an independently known permeability can constrain the suspension's compressibility or dilatancy law.