Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 22 3 c Solution Created 2026-10-03 Updated 2026-10-06
The right-adjoint criterion using comma-category colimits is as follows. Under the given colimit-preservation hypothesis, with preservation including the possibly large colimits below, has a right adjoint exactly when, for every , the projectionhas a colimit in . The right adjoint is obtained from these comma-category colimits. Thus the objects to construct areFor necessity, if with adjunction counit , is a terminal object of the comma category . Its unique incoming morphisms give a colimit cocone for , exactly as for the elements projection in the preceding part.
For sufficiency, choose such a colimit with legs . The morphisms are a cocone on . Since preserves this colimit, there is a unique satisfyingEach is thus a morphism in the comma category. The original colimit cocone gives for every object, hence by the universal property. For any other morphism , cocone compatibility givesSo is a terminal object. Equivalently, represents the categorical presheaf , via . The functoriality of chosen representations makes these into , yielding a natural bijectionThe preservation of these possibly large colimits is essential to the construction of . Under a small-only interpretation, the preceding ordinal counterexample also disproves the unqualified converse here. Take . It preserves all small colimits. For a nonempty set , the comma category has one object over each ordinal and none over , so its projection has colimit . For , the projection is the identity of , again with colimit . Thus all these projection colimits exist, but has no right adjoint: the categorical presheaf is not representable. This makes the large-preservation qualification substantive.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 119 2 ii Solution Created 2026-10-03 Updated 2026-10-06
Apply condition with the singleton . It says that the category of elements has all finite limits, including a terminal object. The opposite category therefore has all finite colimits. In particular it is nonempty; two objects map to their binary coproduct in a category; and any parallel arrows are equalized by their coequalizer. These are precisely the conditions for a filtered category. Equivalently, every finite diagram has a cocone, obtained by reversing a categorical limit in . Thus
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 119 2 i Solution Created 2026-10-03 Updated 2026-10-06
First address the unnumbered preliminaries. The Yoneda lemma gives a natural transformation bijectionThe element corresponds to for . These bijections are natural in and ; the contravariant form replaces by .
Let be the category of elements. Its objects are with ; an arrow is with . Since is a small category, is small. Define a diagram in a category byFor the opposite of , the map is precomposition with . The Yoneda lemma gives a cocone under a diagram whose component sends to .
For any , a competing cocone under a diagram amounts, by the Yoneda lemma, to elements satisfyingThis is exactly the naturality condition for defined by . It gives a unique natural transformation factoring the cocone. Thus the universal property of a colimit proves the canonical colimit presentation of a covariant set-valued functor:The opposite on is essential for the variance of the representable functors.
We now prove the four conditions equivalent by the cycle . Suppose is a finite-limit-preserving set-valued functor. For a finite diagram in a category in the comma category , write its objects as . Take in . Since preserves this finite limit, the compatible maps determine a unique whose composites with are . The pair has the required categorical limit property in , by the same universal properties. For the empty diagram, is a singleton, so there is exactly one map ; this provides the terminal object. Hence for every set .
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 119 2 iv Solution Created 2026-10-03 Updated 2026-10-06
Suppose , where is a filtered category and every is a representable functor. Every covariant representable functor preserves all existing categorical limits: maps from into a limiting object are exactly compatible families of maps into its diagram.
For a finite diagram in a category , use pointwise colimits in the functor category, preservation by each , and the permitted result that filtered colimits commute with finite limits in sets to obtainThe isomorphism is the canonical comparison, since every step respects the limiting projections. This also covers the empty finite diagram and hence the terminal object. Thus , completing the cycle:
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 119 5 a Solution Created 2026-10-03 Updated 2026-10-06
First supply the unlettered preliminaries. Assuming the relevant categorical limits and colimits exist, limits of shape commute with colimits of shape when for every functor the canonical mapis an isomorphism. To construct this map, for each compose the limiting projections with the th colimit injections. They form an -cone, giving a map into the right-hand categorical limit; these maps form a -cocone, giving the comparison. This specifies the actual comparison required for commutation of limits and colimits.
A group regarded as a one-object category has its group elements as arrows, with composition given by multiplication. A functor from it to the Category of sets is a group action. For a -set , a cone consists of a map into whose values are fixed by every . Hence its categorical limit is the set of fixed points of a group action. A cocone is a map out of constant on orbits of a group action; its universal quotient is the orbit set. Thus
A diagram in a category is a set with commuting group actions of and . Its limit–colimit comparison isCommutation makes stable under . The comparison is always injective: if two -fixed representatives are in the same -orbit in , they already determine the same orbit in .
For surjectivity under the finite coprime hypotheses, let be an -orbit fixed setwise by . Its size divides by the orbit-stabilizer theorem. Since the group actions commute and is transitive on , all -orbits inside have the same size : the bijection identifies the -orbits of and . Thus divides , while the orbit-stabilizer theorem also gives . The orders are coprime, so . Every point in is therefore -fixed, and lies in the image of . We have proved commutation of fixed points and orbit quotients for coprime groups:The bijection is the canonical comparison and is natural in the set with commuting group actions, so it proves the requested commutation of limits and colimits in the Category of sets.
Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 119 3 Solution Created 2026-10-03 Updated 2026-10-05
A diagram in a category of shape is a functor . A categorical cone with vertex is a family satisfying for every . A morphism between categorical cones from to is a morphism with for all . A categorical limit is a terminal object in this category of cones: each cone has a unique such morphism to the limiting cone.
For a finite , form the products in a categoryDefine with -coordinates and . The equalizer imposes exactly the cone equations. Therefore gives a categorical limit of , since maps into encode families of legs and factoring through encodes their compatibility. The empty product in a category is the terminal object, covering the empty diagram. This is the construction of small limits from products and equalizers, restricted to finite shapes.
Now take an initial functor and a categorical cone over . For each and each object of the comma category , consider . A morphism there satisfies , soSince is a nonempty connected category, this common value is independent of the object. Define it to be . This does not require choosing representatives: the value is uniquely determined.
For , replacing by proves . Taking proves . Conversely, extending a restricted cone recovers its original legs, since . A vertex morphism commuting with every also commutes with each , and the converse follows by restriction. Thus extension and restriction are strictly inverse functors, not merely an equivalence of categories. This proves cone restriction along an initial functor.
If has all categorical limits of shape , transport a terminal object in the cone category of across this isomorphism to obtain a categorical limit of . Uniqueness of the induced comparison, and its compatibility with natural transformations of diagrams, givesFor the converse use the representable test for initial functors. For , the representable presheaf is equivalently a diagram in a category . Its categorical limit in the opposite category is the colimit of in sets. Elements of that colimit are connected components of the category of elements, equivalently of the opposite category of the slice . This slice has terminal object , so that colimit is a singleton.
For the restricted presheaf , the same description identifies its colimit with the connected-component set of . Indeed a relation identifying with is exactly a generating edge of the zigzag relation in this comma category. The assumed isomorphism of limit functors forces this set to be a singleton. Therefore is nonempty and connected for every , proving
Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 119 4 Solution Created 2026-10-03 Updated 2026-10-05
A monad on is an endofunctor with natural transformations and satisfyingAn algebra for a monad is with and . A morphism of algebras for a monad satisfies . These form the Eilenberg-Moore category . Its free algebra functor is , and its adjunction to the forgetful functor has the explicit bijection
Write , , and let be the coproduct in a category injections. SetHere is an algebra morphism, with underlying multiplication . For an algebra , an algebra morphism corresponds to , and the transposes of are respectivelyFor the second formula, by naturality of and the monad unit law. Thus exactly when, writing ,These say precisely that and are morphisms of algebras for a monad. Consequently any coequalizer of represents pairs of algebra morphisms out of and , proving the coproduct presentation for monad algebras:Its two algebra injections have underlying morphisms and ; the equivalence just proved verifies both the algebra equations and their universal property.
The displayed pair is a reflexive pair, with common sectionIndeed by the algebra unit laws, whileNow suppose has all finite colimits and preserves reflexive coequalizers. The permitted creation theorem gives reflexive coequalizers in : the underlying pair is reflexive and its coequalizer exists and is preserved by . The preceding construction therefore gives binary algebra coproducts in a category. The initial object is , since the free algebra functor is a left adjoint and is initial in .
For any algebra pair , the augmented pairis a reflexive pair, with common section the injection of , and has exactly the same coequalizing morphisms as . Hence all coequalizers exist in . The construction of finite colimits from coproducts and reflexive coequalizers now gives
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 119 2 i Solution Created 2026-10-03 Updated 2026-10-05
Let be the given cocone under a diagram. For , choose an object of the comma category and defineSuch a choice exists because is a final functor. If gives a morphism , so , the cocone relation givesThe connected category condition makes the result independent of the choice along any zigzag.
For , choose ; then is available for , giving . Thus the maps form a cocone under a diagram on . Choosing shows that restriction recovers . Any extension must satisfy , proving uniqueness. This is cocone extension along a final functor.
If has a colimit, extend its universal cocone in this way. Every cocone on restricts to one on , factors uniquely through that colimit, and then agrees with its extension by uniqueness. Hence the same vertex is a colimit of . In particular,and existence of all -shaped colimits in implies existence of all -shaped colimits.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 119 3 i Solution Created 2026-10-03 Updated 2026-10-05
A reflexive pair has a common section with . Form the pushout in a category of and , and write its two maps from as . Its relation , composed with , gives . Thus . Any with gives the compatible pair for this pushout and therefore factors uniquely through . This proves the coequalizer of a reflexive pair from a pushout construction.
There is a genuine transcription difference: the original PDF says finite products in the finite-colimit assertion, while the TeX says finite coproducts. The PDF assertion is false with products. Even retaining a pushout-existence assumption, the full subcategory of the Category of sets on nonempty sets has finite products, pushouts, and all coequalizers, but no initial object, hence no empty colimit. Regard the poset with elements , orderand incomparable as a category. It has finite meets and top , hence finite products in a category. Every reflexive pair in a poset is an equal pair and has its identity as a coequalizer. But have no least upper bound, so they have no coproduct in a category.
For the corrected construction using finite coproducts, let be a finite diagram in a category. PutDefine on the summand indexed by as and . Maps with are exactly cocone under a diagram data on . Hence their universal coequalizer is its colimit. Replace by the reflexive pairwhose common section is the second injection and whose coequalizer is unchanged. This proves construction of finite colimits from coproducts and reflexive coequalizers, including the empty diagram via the empty coproduct:
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 119 5 iv Solution Created 2026-10-03 Updated 2026-10-05
Let be a tiny object of , and let be the initial object of . The representable functor is the terminal functor, since each of its values is a singleton. The exponential adjunction and the Yoneda lemma giveSince is tiny, is itself a left adjoint, so preserves all colimits. Evaluation at also preserves colimits, because they are pointwise in a set-valued functor category. Therefore preserves the coproduct construction.
It also preserves epimorphisms. Indeed, every such epimorphism is a pointwise epimorphism in a functor category, hence the coequalizer of its kernel pair, as can be checked pointwise in sets. A left adjoint preserves that coequalizer and therefore sends it to a regular epimorphism, which is an epimorphism; evaluation at zero preserves surjectivity. Thus is an irreducible projective in a set-valued functor category.
A Cauchy-complete category is one in which every idempotent morphism splits. By the characterization allowed in the question, irreducible projectives are representable functors for such an indexing category. Applying it to proves the tiny covariant functor on a Cauchy-complete category with an initial object is representable conclusion:
Past exam of the mathematics course of the University of Cambridge 2019 iii Paper 119 6 c Solution 2026-10-03
Assume has finite products and every idempotent morphism splits. For a representable presheaf , the exponential formula givesThus exponentiation by is precomposition with . Precomposition has a Right Kan extension as right adjoint, so every representable presheaf is a tiny object.
Conversely, let be tiny. Then is a left adjoint and preserves all small colimits. Since has a terminal object , the terminal presheaf is , and evaluation at preserves colimits. Thereforepreserves all small colimits as a functor of . By the result supplied in the question, splitting idempotents implies that is representable. Hence the representable presheaves are the tiny objects of an idempotent-complete finite-product category, and Yoneda identifies with the full subcategory of tiny objects of its presheaf topos.
Past exam of the mathematics course of the University of Cambridge 2021 iii Paper 119 3 Solution 2026-09-28
A cocone under a diagram with vertex is a natural family , so for every . A colimit of is an initial such cocone: for every cocone , there is a unique with for all .
Let be a final functor and let be a cocone under . For each , choose an object of the nonempty comma category and defineA morphism in the comma category gives , and the cocone identity shows that the two resulting maps are equal. Because is a connected category, a zigzag proves independence of the chosen object. The same construction applied after a morphism proves naturality, so is a cocone. Any extension must have this value because it must satisfy the cocone identity along , proving uniqueness. This is cocone extension along a final functor.
If is a colimit of , its universal cocone extends uniquely to . Restriction and extension give mutually inverse correspondences between cocones from and from , so the extended cocone is a colimit of . Therefore the existence of all colimits of shape implies the required colimits of shape .
Now suppose is a sifted category. For , the product functor is a left adjoint, so it preserves colimits. Applying this once in each variable givesThe diagonal is final, so the right side isThus preserves binary products in a category. Since is connected, the colimit of the constant singleton diagram is a singleton, so it also preserves the terminal object. It therefore preserves finite products.
Past exam of the mathematics course of the University of Cambridge 2026 iii Paper 119 1 Solution Created 2026-09-24 Updated 2026-09-25
A category is well-powered when the isomorphism classes of monomorphisms into each object form a set. For , every subobject is represented by a subfunctor with . Since is small, all choices lie in the set , and naturality merely cuts out a subset. Thus the functor category is well-powered. Quotients are similarly represented by compatible equivalence relations on the sets , so they form a subset of ; hence it is well-copowered.
A cocone under the identity diagram consists of maps satisfying for every . A terminal object supplies the unique such cocone and has the required universal property. Conversely, if is a colimit of the identity, both and mediate its cocone to itself, so uniqueness gives . For any , cocone compatibility gives ; thus there is exactly one arrow , and is terminal.
For , let be the set of isomorphism classes of quotients of the representable . This is a set by well-copoweredness. A map sends a quotient of to the image quotient of the composite , making a functor. For any functor and , Yoneda gives ; factor it as an epimorphism followed by a monomorphism and send to the resulting quotient class. These maps agree along every monomorphism. Conversely, a cone with apex assigns to a quotient the element obtained by applying its leg at to . Yoneda and epi-mono factorization show that this is well-defined and is the unique map . Therefore is a local state classifier.
An object of is a finite set with a permutation. For each , let with trivial action and map a finite -set to by sending every point to the length of its orbit modulo . Equivariant injections preserve orbit lengths, so these maps form a cocone under the monomorphism subcategory; varying cyclic orbits shows that its legs are collectively surjective. If a local state classifier existed, its universal map onto every would be surjective because the universal legs are jointly epic. This would force the finite set to have at least elements for every , a contradiction.
A functor admitting a further left adjoint must itself be a right adjoint and preserve all existing categorical limits. A functor admitting a further right adjoint must preserve all existing colimits. Failure to preserve a single terminal object, equalizer, initial object or coproduct therefore rules out the corresponding extension. In the adjoint chain for the objects of a category, connected components fail an equalizer and the indiscrete category functor fails a binary coproduct.