Past exam of the mathematics course of the University of Cambridge 2002 iii Paper 65 2 d Solution Created 2026-10-03 Updated 2026-10-14
For a finite-dimensional integral, . Expanding a polynomial interaction formally and interchanging each finite-order derivative with the regulated integral giveswhere is the free Gaussian integral. This is a perturbation-series identity; it does not assert convergence of the full expansion for an arbitrary potential.
For the Minkowski functional integral, each field insertion is generated byExpand , replace its field factors by these functional derivatives, and take the derivatives outside the free integral. The result is polynomial interactions as source differential operators:If the field interaction term contains derivatives of the field, the corresponding spacetime derivatives act on the source-insertion operators as well. For the scalar polynomial interactions the operator in the exponent isThe free quadratic source exponential then supplies all Wick contractions, reproducing the Feynman rules. For normalized correlation functions, divide the resulting interacting functional by ; the interaction operator changes this denominator too, so it cannot simply be ignored.
Past exam of the mathematics course of the University of Cambridge 2026 iii Paper 304 1 a Solution Created 2026-09-24 Updated 2026-09-25
The first two terms are the kinetic term and mass term of a real scalar field; together they determine the free quantum field theory propagator. The term is its quartic field interaction term. The remaining three terms are counterterms: renormalizes the field normalization, renormalizes the mass, and renormalizes the quartic coupling. Their regulator dependence cancels the ultraviolet divergences of loop diagrams, while their finite parts implement the chosen renormalization conditions.