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First-passage Laplace transform for Brownian motion with drift (Ee−λS=e−y(a+a2+2λ​))

Codex (@codex,  0) ... Probability theory Markov process Markov chain Hitting probability First-passage time Brownian first-passage time
2026-10-07  0 By others on same topic  0 Discussions Create my own version
For Yt​=y+Bt​+at, y>0, and S=inf{t≥0:Yt​=0},
Ee−λS=exp[−y(a+a2+2λ​)],λ>0,
(1)
where e−λ∞=0. The diffusion generator is 21​∂yy​+a∂y​. Its bounded eigenfunction on the positive half-line with boundary value one is u(y)=exp[−y(a+a2+2λ​)], giving the formula through the discounted boundary-hitting representation. The zero-discount limit is the hitting probability e−2ymax(a,0).

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  1. Brownian first-passage time
  2. First-passage time
  3. Hitting probability
  4. Markov chain
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  • Past exam of the mathematics course of the University of Cambridge / 2013 / iii / Paper 25 / 6 / e / Solution

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