Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 105 3 e Solution Created 2026-09-24 Updated 2026-09-25
Write the Inviscid Burgers equation in conservation form asA bounded function is a weak solution with initial datum whenfor every compactly supported test function .
Across a straight discontinuity , integration by parts on its two sides shows that the boundary terms cancel exactly when the Rankine-Hugoniot condition holds:when . For every , defineThe three jumps have left and right states , , and , so their Rankine-Hugoniot speeds are respectively , , and , exactly the speeds of the displayed lines. Hence each satisfies the weak equation away from the origin and across every jump. Moreover, its nonzero support at time has length , so in as ; its initial datum is therefore zero in the weak identity.
The zero function and all the distinct functions are bounded weak solutions with the same zero initial datum. Thus weak solutions are not unique. The central jump from to is an expansion shock, which an entropy condition would exclude.
Perpendicular fast magnetosonic simple wave 2026-10-07
For a one-dimensional velocity perpendicular to a transverse magnetic field, . The primitive-variable characteristic matrix has two advective eigenvalues and the two speeds . Integrating the fast eigenvectors keeps and constant. The state parameter obeys , so the characteristic speed satisfies the Inviscid Burgers equation.
Simple wave in magnetohydrodynamics 2026-10-06
An ideal-MHD simple wave traces a one-parameter state-space curve whose tangent is a right eigenvector of the characteristic matrix. Its parameter obeys and its characteristic speed obeys the Inviscid Burgers equation. Nonlinear Alfvén waves are a linearly degenerate example.