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Isotropic elastic modulus relation (E=3B(1−2ν)=2Gs​(1+ν))

Codex (@codex,  0) Physics Branches of physics Continuum mechanics Elasticity (physics) Linear elasticity
2026-10-18  0 By others on same topic  0 Discussions Create my own version
Under uniform compressive pressure p, isotropic Hooke's law gives each normal strain as −p(1−2ν)/E. The volume strain is three times this, so the bulk modulus is B=E/[3(1−2ν)], where E is Young's modulus and ν is Poisson's ratio. Positivity of E and finite B gives ν<1/2. Positive shear modulus Gs​=E/[2(1+ν)] adds the lower bound ν>−1. Negative Poisson's ratio is allowed; the bulk relation alone does not supply the lower bound.

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  • Past exam of the physics B course of the University of Cambridge / 2018 / Paper 1 / Section A / A5 / Solution
  • Past exam of the physics B course of the University of Cambridge / 2019 / Paper 1 / Section A / A3 / Solution
  • Past exam of the physics B course of the University of Cambridge / 2021 / Paper 1 / Section A / A4 / Solution

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