Linear drag opposes the velocity relative to the surrounding medium with magnitude proportional to its speed, where . Its power is , so it dissipates kinetic energy. Under a constant external force, the resulting linear ordinary differential equation relaxes exponentially on the time scale .
For constant acceleration vector and , a projectile initially at with velocity has
The integrating factor solves the first-order linear ordinary differential equation for the velocity; one more integration proves the position formula. The terminal velocity is , and is the relaxation time. For and , eliminating time when gives
For finite , the physical domain is . If , the path is vertical and cannot generally be represented as a single-valued graph . Expanding at fixed as recovers .
Mechanical mobility relates a steady drift velocity to a weak applied mechanical force. For isotropic linear drag , terminal force balance gives with , in units . For a sphere obeying Stokes's law, it is . The corresponding translational hydrodynamic mobility matrix is . The Stokes–Einstein relation reads , and the velocity relaxation time is . In the bare-force spherical model, a particle with electric charge has electrophoretic mobility ; ionic-atmosphere effects can modify that simple model.
When momentum relaxes much faster than the imposed motion, force balance replaces the inertial equation: in a deterministic one-dimensional model. The linear friction coefficient sets the time scale. Thermal forcing, if included, gives overdamped Langevin dynamics.
The dimensional linear friction coefficient relates drag force and velocity, , and has units of force divided by speed. It differs from the dimensionless aerodynamic drag coefficient. For an isolated sphere in Stokes flow, the Stokes drag law gives .
For constant downward gravitational acceleration and linear drag , the upward velocity solves with . Its first zero occurs at the displayed time. The dimensionless control variable is , and the limit gives .

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