Past exam of the mathematics course of the University of Cambridge 2005 ii Paper 2 6E c Solution Created 2026-09-24 Updated 2026-09-24
Past exam of the mathematics course of the University of Cambridge 2005 ii Paper 3 13E e Solution Created 2026-09-24 Updated 2026-09-24
Past exam of the mathematics course of the University of Cambridge 2015 ii Paper 4 11E b Solution Created 2026-09-24 Updated 2026-10-06
Let and . In the linear noise approximation, and . At the stationary mean, the preceding moment identity gives . Hence the stationary covariance matrix solves the Continuous Lyapunov equationwhich is precisely the requested component formula because is symmetric.
Past exam of the mathematics course of the University of Cambridge 2022 ii Paper 3 6C c Solution Created 2026-09-24 Updated 2026-09-25
The deterministic drift vanishes at the positive stable pointWhen is large, fluctuations sample only a narrow range around it, so the linear noise approximation replacesThe resulting Ornstein-Uhlenbeck stationary density is the stated normal distribution withand
Past exam of the mathematics course of the University of Cambridge 2023 ii Paper 4 14C Solution Created 2026-09-23 Updated 2026-10-03
This is a birth-death process with birth and death ratesIts transition diagram has the two arrowsThe gain into state comes from a death in state or a birth in state , while the loss is the sum of both rates out of state . The birth-death master equation is consequently
Multiplying by , summing over the nonnegative integers, and shifting the summation indices shows that each birth contributes and each death contributes . Thus the first-moment equation of a birth-death process givesAt a stationary state, use the variance identity . Solving the resulting quadratic equation givesThe minus root is inadmissible whenever it is negative, namely when . Equality would give zero mean, which is also incompatible with a positive immigration rate , so for the minus branch requires even to be a possible mean.
For a continuum approximation, write and . Applying the Kramers-Moyal expansion to the two gain terms and retaining derivatives through second order gives the Fokker-Planck equationwhere the negative drift and infinitesimal jump variance areThis truncation requires the typical population and the scale on which varies to be much larger than the unit jump size, with the rates varying smoothly across that scale.
The positive zero of isso in particular as . Put . The linear noise approximation useswhereand, because ,In a stationary state with zero Fokker-Planck probability current,Its normalized solution is the normal distributionIt follows that
These estimates agree with the exact stationary first-moment relation on its plus branch to leading order: inserting gives . Moreover,Thus the stationary mass lies far from the boundary , is narrow relative to its mean, yet changes across many lattice sites. These are precisely the large-population and slow-variation conditions needed for the diffusion approximation.