Sobolev space with a partial Dirichlet condition Created 2026-09-24 Updated 2026-11-05
Let be a bounded Lipschitz domain and a measurable portion of its boundary. The spaceis a closed vector subspace of the H1 space. The Sobolev trace operator maps continuously into , and restriction to is bounded, so is the kernel of a continuous linear map. Boundary regularity is what makes this ordinary trace formulation available.
No positive-measure assumption is needed for closedness. If is also connected and has positive surface measure, the Poincare inequality with a partial Dirichlet boundary controls the full Sobolev norm by the gradient norm on .
Strict monotonicity without coercivity on H1 Created 2026-10-31 Updated 2026-11-05
Let be a nonempty bounded Lipschitz domain, and define byThis operator is strictly monotone: the difference pairing is the sum of and the nonnegative integral , which is strictly positive wherever . The bounded-domain hypothesis also makes nonzero constant functions admissible in .
For constant ,Thus is not a nonlinear coercive operator in the large-norm sense. On , the Poincaré inequality instead giveswhich proves coercivity on that zero-boundary space. The example separates being a strictly monotone operator from coercivity and identifies the uncontrolled constant direction.
Trace operator 2026-10-14
On a bounded Lipschitz domain, the Sobolev trace operator is the continuous linear extension to of the boundary restriction of smooth functions. Continuity and density make this extension unique; its existence is the Sobolev trace theorem. The kernel prescribes a homogeneous Dirichlet boundary condition. Vanishing Sobolev trace on only part of the boundary instead gives the form domain for a mixed boundary condition, with the natural Neumann boundary condition on the remainder. On an assembly of congruent tiles, taking a Sobolev trace commutes with a constant matrix acting on the tile restrictions. This lets a transplantation theorem be proved on quadratic form domains even when corner eigenfunctions have singular classical derivatives.
On a bounded Lipschitz domain, the Poisson equation with Robin boundary condition has the displayed weak formulation in when is a bounded boundary coefficient. Boundary integrals use Sobolev traces. It follows from Green's first identity, requiring only first weak derivatives of . If is uniformly positive, testing the difference of two solutions against itself proves uniqueness: its gradient and its boundary Sobolev trace vanish. The Poincare inequality with a boundary trace also makes this a coercive bilinear form.
Weak mixed Poisson problem Created 2026-09-24 Updated 2026-11-05
Let be a bounded connected Lipschitz domain, and let a measurable boundary part have positive surface measure. Impose a homogeneous Dirichlet boundary condition there and a homogeneous Neumann boundary condition on the remainder. For , seek in the closed Sobolev space subspacesatisfyingThe Trace operator makes the boundary restriction meaningful. The Poincare inequality with a partial Dirichlet boundary bounds the full norm by the gradient norm on . Thus the left side is a bounded coercive bilinear form, and the Lax-Milgram theorem gives a unique weak solution. The same proof allows any bounded linear functional on as the right side.
The Neumann condition is natural: integration by parts leaves the boundary term on the non-Dirichlet portion, and requiring the identity for all makes that term vanish. If is empty, constants remain in the kernel of a linear map; for homogeneous Neumann data, compatibility requires , and uniqueness requires a normalization such as zero mean. Positive Dirichlet surface measure is what removes this ambiguity.
Zero-mean bounded-variation space Created 2026-09-29 Updated 2026-10-05
The zero-mean bounded-variation space isOn a bounded connected Lipschitz domain, removing the constant nullspace makes total variation coercive on this subspace by the Poincaré inequality for total variation.