Osgood uniqueness criterion 2026-10-07
If a continuous nondecreasing modulus satisfies this divergence condition, an estimate with locally integrable gives uniqueness of characteristic curves. Apply a regularized integral comparison to their separation. For the log-Lipschitz modulus, gives while . Zero initial separation stays zero. Unlike the usual linear Gronwall inequality, this criterion allows non-Lipschitz vector fields.
Past exam of the mathematics course of the University of Cambridge 2012 iii Paper 7 2 e Solution 2026-10-07
For , . The printed upper bound is negative whenever , so it cannot bound a nonnegative difference. The correct small-distance modulus is , and the radius in the hint must also be positive.
Write , , and . Then . Denote the planar vorticity velocity kernel by . It satisfies and . Split the integral at radii and about .
On , every point of the segment joining and remains at least from . The mean value theorem bounds the kernel difference by , giving a contribution at most .
On , use the sum of the two kernel magnitudes instead of their derivatives. This disk lies inside a disk of radius about either . Hence its contribution is bounded by . Combining the three regions yieldsAt coincident points the difference is zero. At larger distances use the boundedness from part (d). A convenient global log-Lipschitz modulus isgiving . This is positive, continuous and nondecreasing. It also proves continuity of .
Past exam of the mathematics course of the University of Cambridge 2012 iii Paper 7 2 f Solution 2026-10-07
Literally, the printed hypothesis with positive is impossible for pairs at distance less than one, even when is constant. Use the corrected log-Lipschitz modulus from part (e). Local existence for the continuous finite-dimensional vector field follows from the Peano existence theorem. Boundedness gives . Thus a trajectory cannot escape to infinity in finite time; at a finite endpoint it has a limit, and local existence there extends it. Solutions exist globally.
For uniqueness, let have the same initial point and set . This absolutely continuous function satisfies, almost everywhere,This is the Osgood uniqueness criterion, rather than the usual linear Gronwall inequality, because the velocity need not be Lipschitz continuous. To see the argument directly, put . As long as , monotonicity of givesFor , this becomes . Integration givesFor any fixed finite interval, this upper bound tends uniformly to zero as . Taking small prevents a first exit through , so the bound remains valid throughout that interval. Thus . Backward time has the same proof. Every initial point has exactly one global trajectory.
The decisive fact is . For different nearby initial points, the same comparison givesuntil the separation reaches one. This quantitative continuous dependence makes the flow a homeomorphism, although it need not be a smooth diffeomorphism.
Past exam of the mathematics course of the University of Cambridge 2012 iii Paper 7 2 g Solution 2026-10-07
For smooth vorticity, parts (b)--(c) and the transport equation give and measure preservation. The change of variables formula therefore conserves and . Parts (d)--(e) give a uniformly bounded velocity and a uniform log-Lipschitz modulus; applying the time-dependent version of part (f) constructs unique global characteristic curves.
For a rough Yudovich characteristic flow, state the needed temporal hypothesis explicitly:The usual weak Euler solution class provides these conditions and the initial time trace. On , put . The velocity bounds are and , with integrable on this interval.
For completeness, mollify spatially. The resulting smooth velocities have trajectories and obey the same speed and modulus bounds, up to one common constant. Their speeds have the integrable majorant , giving uniform boundedness and equicontinuity of trajectories. Arzela-Ascoli theorem supplies a uniformly convergent subsequence. The modulus estimate controls , while the spatial mollification error tends to zero with an integrable majorant. Thus the limit solvesReplace by in the Osgood uniqueness criterion proof. It gives uniqueness and prevents finite-time escape. The characteristics are globally uniquely defined for each given Euler solution in the usual Yudovich class. This constructs the flow for a fixed solution; it is not by itself the entire uniqueness proof for the nonlinear Euler equation.
Merely saying that both spatial norms are finite separately at each time does not state the local temporal bound or measurability used in this argument. The printed formulation must be interpreted in the usual solution class, or supplemented with these temporal conditions. Also, an initial datum here is a function of ; the extra time variable in the displayed initial-data space is extraneous.
Planar vorticity velocity kernel 2026-10-07
The velocity induced by planar vorticity is a convolution with this kernel, whose sign depends on the stream function and vorticity conventions. Its magnitude is and its derivative is bounded by . Splitting the convolution at radius gives . The same singularity yields a log-Lipschitz modulus, enough for a Yudovich characteristic flow.
Yudovich characteristic flow 2026-10-07
For a planar Euler velocity obtained from vorticity in , the planar vorticity velocity kernel gives a locally integrable speed bound and log-Lipschitz modulus. Spatial mollification gives existence of global trajectories; the Osgood uniqueness criterion gives uniqueness and continuous dependence. Measurability in time and an initial trace are needed. This establishes the flow for a fixed Euler solution; nonlinear uniqueness of the Euler solution itself requires further comparison arguments.